5.2 Review
Vocabulary
Binomials
two terms
Trinomials
has three terms
Factoring
a method to find products
Monomial
An expression that has only one term. This is the first step to factoring.
Quadratic Equation/Standard form
one variable that can be written in the form of ax2+bx+c=0
Factoring Equations x2+bx+c=(x+m)(x+n) =x2+(m+n)+mn ax2+bx+c=(kx+m)(x+n) =klx2+(kn+lm)x+mn
* Example 1 *
 

x2-12x-28

 

-Determine which factoring equation to use. In this case, the equation is

-x2+bx+c=(x+m)(x+n)
        =x2+(m+n)+mn

 

 

-So…..

 

x2-12x-28=(x+m)(x+n)

-12 is B and -28 is C

 

m+n=-12

mn=-28

 

-Factor

 

Factors of -28(mn)
 [-1, 28]
 [-2, 14]
 [2, -14]
 [-4, 7]
 
Sum of factors(m+n)-
 [27]
 [2]
 [-12]
 [3]
 

 

-Solve

 

m=2, n=-14

 

>> x2-12x-28=(x+2)(x-14)

 
* Example 2 *

3x2-17x+10

 

-use  

 

ax2+bx+c=(kx+m)(x+n)

       =klx2+(kn+lm)x+mn

 

3x2-17x+10=(kx+m)(lx+n)

 

-k and l are factors of 3 while m and n are factors of 10

 

-Factor and Solve

(3x-10)(x-1)=3x2-13x+10

(3x-5)(x-2)=3x2-11x+10

(3x-1)(x-10)=3x2-31x+10

(3x-2)(x-5)=3x2-17x+10

 

-Answer

3x2-17x+10=(3x-2)(x-5)
Tips>> Special Factoring Patterns
 
Difference of 2 squares   

Pattern: 

	a2-b2=(a+b)(a-b)
                                   
Ex:	x2-9=(x+3)(x-3)



Perfect square trinomial

 
 	a2+2ab+b2=(a+b)2
Ex:	x2+12x+36=(x+6)2
 
 
 	a2-2ab+b2=(a-b)2
Ex:	x2-8x+16=(x-4)2

*Example 3 *

A) 4x2-25=(2x) 2-5x2                  difference of 2 squares

       =(2x+5)(2x-5)

 

B) 49r2-14r+1=(7r) 2 -2(7r)(1)+12      perfect square trinomial

            =(7r-1) 2

 

 
* Example 4 *

A)5x2-20=5(x2-4)                          factor

       =5(x+2)(x-2)

 

B)6p2+15p+9=3(2p2+5p+3)

          =3(2p+3)(p+1)

Tip>> a quadratic equation/standard form in one variable can be written in the ax2+bx+c=0 form

 
* Example 5 *

A) x2+3x-18=0                                 factor

    (x+6)(x+3)=0                    

    (x+6)=0   or x-3=0

    x=6 or -3

 

B)2t2-17t+45=3t-5

   2t2-20t+50=0                            write in standard form

   t2-10t+25=0                              divide by 2

         (t-5)2=0                           factor 

         t-5=0                            use 0 product property

         x=5

GUIDED PRACTICE :)

1)2x2+x-3(factor the expression)

2)q2+2(factor the expression)

3)x2-2x-8=0(solve the equation)

4)5w2=30w(solve the equation)

5)y=x2+6x+8(write the function in intercept form)

6)y=3x2-8+4(write the function in intercept form)

7)x2-25(equations in special patterns)

8)9s2+12s+4(equations in special patterns)

9)5x2+5x-10(factoring monomials first)

10)u2+7u(factoring monomials first)

11)x2-3x-4=0(equations in standard form)

12)-3b2+3b+90=0(equations in standard form)