Welcome to
Graphing Parabolas
By
Sahand Reiisieh
Parabola:
The set of all points equidistant from a point
called the focus and a line called the directrix. The
focus lies on the axis of symmetry, and the directrix
is perpendicular to the axis of symmetry.
Note:
The graph of a quadratic formula y = ax2 + bx
+ c is a
parabola
Keys to
Success:
. Find the axis of symmetry.
The axis of symmetry is an imaginary dashed line that
runs through the vertex equally dividing the parabola
in half. The formula for finding the line of symmetry
is x = -b/2a
. Find
the X and Y intercepts. These are the EASIEST points
to find to help find the point on your parabola. These
points can be found by setting X to zero and solving
for Y, and vice versa.
. A positive ax2 gives you a parabola in the shape
of a smiley face. Any negative coefficient before the
ax will give you a parabola shape of a sad of frowning
face ( an upside down U).
. To find the vertex simply
take the value of X found by computing the axis of
symmetry. Insert that value for all X's in the
quadratic equation and solve for Y. The values of
(X,Y) will be your vertex in which the axis of
symmetry runs through.
Graph y=2x2-8x+6
Step 1: Find the line of
symmetry
. x=-b/2a
. x= -8/4
. x = 2
Step 2: Plug the value of
x=2 into the equation.
. y= 2(2)2-8(2) + 6
. y= -2
Step 3: Plot the
Vertex
. (2,-2)
Step 4: Find more
points!
. Set x to zero to find the Y
intercept.
. y= 2(0)2-8(0) + 6
. y= (0, 6)
Step 5: Use
Symmetry
. Use symmetry to plot more points by referring
to the axis of symmetry.
. Since (0,6) is -2
spaces away from the axis simply move over +2 spaces
to the right of the axis to
find a second point (4,6)
Now YOU try =)
Practice problems
Graph the equations. Find
axis of symmetry and vertex
1) y= 2x2-12x+19
2) y= -3x2+0x+5
3) y=-1/6x2-x-3