Solving a System of 2 Equations by Substitution Tutorial
Problem: 10y + x = 6
2y + 3x = 4
Steps:
1. First, look at the two equations and get a variable by itself from the easier equation
Ex: 10y + x = 6 -----> x = -10y + 6
2. Then, plug the variable value into the equation that you didn't do anything to, the 2nd equation.
Ex: 2y + 3x = 4 ----> 27 + 3(-10y + 6) = 4
3. Distribute the 3 to the number in the perenthese and add or subtrat all the numbers to reach the number value for the variabe.
Ex: 2y + 3(-10y + 6) = 4
2y - 30 + 18 = 4
-28y + 18 = 4
-2y = -14
y = -1/2
4. After, plug in the value for the variable that you got in the previous step into the second equation to get the final variable.
Ex: y = -1/2
2y + 3x = 4
2 (1/2) + 3x = 4
5. Finally, add, multiply and subtract to reach the final answer and isolate the variable.
Ex: 2(-1/2) + 3x = 4
1 + 3x = 4
3x = 3
x = 1
6. Write the final answer in (x,y) form.
Ex: (1, -1/2)
Now You Try!
a. 2x + 3y = 5
x - 5y = 9
b. -x + 2y = 3
4x - 5y = -3
c. 6x + 4y = 20
3x + y = 5
d. 7x + 8y = 12
2x + y = 15
e. x + 2y = 2
4x - 5y = -3