Solving a System of 2 Equations by Substitution Tutorial
Problem: 10y + x = 6
         2y + 3x = 4

Steps: 

1. First, look at the two equations and get a variable by itself from the easier equation

                    Ex:  10y + x = 6 ----->  x = -10y + 6


2. Then, plug the variable value into the equation that you didn't do anything to, the 2nd equation.

                    Ex: 2y + 3x = 4 ----> 27 + 3(-10y + 6) = 4

3. Distribute the 3 to the number in the perenthese and add or subtrat all the numbers to reach the number value for the variabe.

                    
                    Ex: 2y + 3(-10y + 6) = 4 
                        2y - 30 + 18 = 4
                        -28y + 18 = 4
                        -2y = -14

                        y = -1/2

4. After, plug in the value for the variable that you got in the previous step into the second equation to get the final variable.

                    Ex: y = -1/2
                        2y + 3x = 4
                        2 (1/2) + 3x = 4

5. Finally, add, multiply and subtract to reach the final answer and isolate the variable.

                    Ex: 2(-1/2) + 3x = 4
                        1 + 3x = 4
                        3x = 3
                         
                        x = 1 

6. Write the final answer in (x,y) form. 

                    Ex: (1, -1/2)



Now You Try!

a. 2x + 3y = 5
   x - 5y = 9

b. -x + 2y = 3
   4x - 5y = -3

c. 6x + 4y = 20
   3x + y = 5

d. 7x + 8y = 12
   2x + y = 15 

e. x + 2y = 2
   4x - 5y = -3