Relations
and Functions
A mathematical concept of relation
“A relation is a set of ordered
pairs.” In other words, a relation is pairing of input values with output
values.
The
set of the first components of the ordered pairs or the input values is called
the DOMAIN. The set of the second components of the ordered pairs or the output
values is called the RANGE.
EXAMPLE: R= {(6, 8), (3, 7), (1, 2), (0,
1)}
In the above example,(6,8),(3,7),(1,2),(0,1)are
the ordered pairs;R is a set of these ordered pairs ,therefore R becomes relation.
In the relation R,{6,3,1,0}is the domain and {8,7,2,1} is the range.
REPRESENTATION OF RELATION:
A) Using arrow diagrams or mapping:
In this form, arrows are drawn from one set
(that constitutes the domain) to another set (that constitutes the range) to
indicate pairings, which satisfy the given relation.
EXAMPLE: R={(1,2),(3,4),(4,5)}
In the above example,
domain or set A= {1, 3, 4} and range or set B={2,4,5}
Using arrow diagrams,
the relation of set A TO set B can be represented in the following manner;


A B
1 2
![]()
3 4
4 5
(B)By Graphing
To graph a relation, plot
the domain on the x-axis of the graph and the range on the y-axis.
EXAMPLE:R={(1,3),(1,5),(2,3),(25),(3,5),(4,5)}
DOMAIN OF R = {1, 2,
3, 4}
RANGE OF R= {3, 5}
NOW plot the ordered
pairs with the first components on the x-axis and the second components on
y-axis.
C) Using x-y table
A
relation can be expressed in two variables, x and y.
In
an x-y table, the components of the domain stand as the variables for “x”
whereas the components of the range are the variables for the “y”.
EXAMPLE:
R= {(1, 3), (2, 4), (3, 6), (4, 8)}
Domain=
{1, 2, 3, 4} which becomes the variables for x
Range=
{3, 4, 6, 8} which becomes the variables for y
|
x |
1 |
2 |
3 |
4 |
|
y |
3 |
4 |
6 |
8 |
D) Using Equations
A
relation can be expressed in two variables using a linear equation when all the
ordered pairs in the relation exhibit a particular characteristic.
Example:
R= {(1, 3), (2, 4), (3, 5), (4, 6)}
In
the above relation ;{ 1, 2, 3, 4} or domain forms the values for the variable “x”
&
{3,
4, 5, 6} or range forms the values for variable “y”
In
each ordered pair, second component=first component +2
In
other words, for every value of ‘x’, there is a ‘y’ value which is equal to 2
added to the ‘x’ value. Hence the relation can be written as:
y=x+2
FUNCTION
A
relation from a set A TO set B is called a FUNCTION; if for each element of set
A there is a unique (one and only one)image in set B.In other words ,a function
is a relation where the first components of all the ordered pairs are
different.
REMEMBER: In a function;
· Every element in set A should have its image
in set B.
· An element of set A must
have only one image in set B.
· The first components
of the ordered pairs cannot repeat but the second components may repeat.
· Every relation which
can be expressed by a linear equation in two variables represents a function.
EXAMPLES:
1)
R={(1,2),3,4),(5,7),(8,10)}
The
above relation is a function because the first components of all ordered pairs
are different.
2)
R={(1,2),(1,6),(2,3)}
The
above relation is not a function because the first components are repeated.
3) A B


![]()
1 8
7
3 6
It
is not a function because one element in A has two images in B.
4)
y=2x-3
The
above relation is a function because for each value of x, there is a unique
value of y.
TRY IT YOURSELF
1)
R={(1,4),(1,5),(2,4),(2,5),(3,4),(3,5),(4,5)}
· What is the domain of
R?
· Find the range of R?
· Depict the relation
by mapping.
2)
R={(1,3),(2,6),(3,11),(4,18),(5,27)}
· Draw an x-y table for
the relation.
· Graph the relation.
· Is it possible to
represent the relation in equation form? If yes ,then write an equation for the
relation.
· Is the relation a
function why?


3) A B

5 6
4 12
8 1
![]()
2 3
6 9
·
Write
the relation in Roster form.
·
Is
the relation a function?
3)
Set
A={3,4,5,6},set B={5,6,7,8,9,10,11}and relation(R) from set A to set B is such
that:
R= {(x, y):y=x+3; ‘x’ belongs to set A & ‘y’
belongs to set B}
· List the elements of R.
· Write the domain and
range of the relation.
· Is this relation a function?
Give reasons.